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Valence Bond Theory

Which of the ...

Question

Which of the following complexes has the least molar conductivity in the solution?

C o C l_{3} .3 N H_{3}

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C o C l_{3} .4 N H_{3}

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C o C l_{3} .5 N H_{3}

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C o C l_{3} .6 N H_{3}

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Solution

The correct option is C $C o C l_{3} .3 N H_{3}$
Molar conductivity is directly proportional to the number of ions produced in the solution.
$C o C l_{3} .3 N H_{3}$ does not dissociate into ions. So, its molar conductivity will be least. $C o C l_{3} .6 N H_{3}$ gives total of $4$ ions, $C o C l_{3} .5 N H_{3}$ gives total of $3$ ions, $C o C l_{3} .4 N H_{3}$ gives total of $2$ ions.

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Similar questions

Q. Draw Werner's structure of the following:
(a)

C o C l_{3} . 6 N H_{3}

(b)

C o C l_{3} . 5 N H_{3}

(c)

C o C l_{3} . 4 N H_{3}

(d)

C o C l_{3} . 3 N H_{3}

Q. The correct order of the stoichiometries of

A g C l

formed when

A g N O_{3}

in excess is treated with the complexes:

C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}

respectively is:

Th correct order of the stochiometrics of AgCl formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is

Q. Given the molecular formula of the hexa coordinated complexes (A)

{C o C l}_{3} . {6 N H}_{3}

(B)

{C o C l}_{3} . {5 N H}_{3}

(C)

{C o C l}_{3} . {4 N H}_{3}

. If the number of coordinated

{N H}_{3}

molecules in

A, B

and

C

respectively are

6, 5

and

4

, primary valency in

(A), (B)

and

(C)

are

Q. The aqueous solution of which of the following complex has the least conductivity under identical conditions.

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