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B
[Cu(NH3)4]2+
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C
[Ti(H2O)6]3+
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D
[Ni(en)2]2+
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Solution
The correct option is C[Fe(CN)6]4− Electronic configuartion: Fe2+−[Ar]3d6 Cu2+−[Ar]3d9 Ti3+−[Ar]3d1 Ni2+−[Ar]3d8 Since CN− is a strong field ligand, it will pair up the electrons in d orbital and hence [Fe(CN)6]4− become diamagnetic.