Which of the following complexes will have four isomers?

[C o (e n) {(N H_{3})}_{2} C l_{2}] C l

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[C o {(P P h_{3})}_{2} {(N H_{3})}_{2} C l_{2}] C l

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[C o {(e n)}_{3}] C l_{3}

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[C o {(e n)}_{2} C l_{2}] C l

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Solution

The correct option is A $[C o (e n) {(N H_{3})}_{2} C l_{2}] C l$
The complex $[C o (e n) {(N H_{3})}_{2} C l_{2}] C l$ has four isomers. In one isomer, two ammonia ligands are trans to each other. In the other isomer, the chlorine ligands are trans to each other. In the third isomer the ammonia ligands are cis to each other and chlorine ligands are also cis to each other. This is optically active and exists in d and l forms. Thus, total four isomers are possible.

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Similar questions

Q. Number of possible isomers for the complex

[C o (e n)_{2} C l_{2}] C l

will be _____________.

Q. The number of possible isomers for the complex

[C o (e n)_{2} C l_{2}] C l

will be: (

e n

= ethylenediamine)

Q. Number of possible isomers for the complex

[C o (e n_{2}) C l_{2}] C l

will be (en: ethylenediamine) is:

Number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] C l$ will be (en = ethylenediamine)

Arrange the following complexes in the increasing order of conductivity of their solution

$[C o (N H_{3})_{3} C l_{3}], [C o (N H_{3})_{4} C l_{2}] C l, [C o (N H_{3})_{6}] C l_{3}, [C o (N H_{3})_{5} C l] C l_{2}$

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