Which of the following compound can exist in an optically active form?

B r H C = C H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - H ∣ C ∣ N H_{2} - C O O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H O O C (C H_{2})_{2} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $C H_{3} - H ∣ C ∣ N H_{2} - C O O H$
The 2-aminopropanoic acid will exist in optically active form as it contains an asymmetric $C$ atom which is a $C$ atom to which 4 different atoms or groups are attached.

Suggest Corrections

Similar questions

\begin{matrix} C H_{3} | H & - & C & - & O H | C O O H \end{matrix}

C H_{3} - O H | C H - C O O H Δ - \to

H O O C - C H (O H) - C H (O H) - C H (O H) - C O O H

X (C_{5} H_{8} O_{2})

C O_{2}

N a H C O_{3}

Y (C_{5} H_{10} O_{2})

Join BYJU'S Learning Program