Which of the following compound can show Fehling's test?
(I) $P h - N H - O H$
(II) $P h - C H O$
(III) $H - O | | C - O H$
(IV) $O H | C H_{2} - O | | C - C H_{3}$

I, III, IV

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I, II, III, IV

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II, III, IV

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I, II, III

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Solution

The correct option is A I, III, IV
Fehling test is shown by aldehyde (having $α$ -hydrogens) and terminal $α$ -hydroxy ketone.
$P h - C H O$ does not react with Fehling solution as it does not have $α$ -hydrogens.
Formic acid also responds positively with Fehling's solution as it can readily oxidise to carbondioxide.
N-phenylhydroxylamine can also reduce Fehling's solution and itself converts to nitroso compound.

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Similar questions

P h - N H - O H

P h - C H O

C H_{3} - O | | C - H (i); C H_{3} - O | | C - C H_{3} (i i); E t - O | | C - H (i i i)

C H_{3} - C H_{2} - C H_{2} - O | | C - H (i v); P h - O | | C - C H_{3} (v); P h - O | | C - P h (v i)

H_{3} C - O | | C - C H_{3}

H_{3} C - O | | C - C H_{2} - O | | C - C H_{3}

P h - O H

H_{3} C - O | | C - O H

p K a

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

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