Which of the following compound has four bond pair and one lone pair?

{N H}_{4}^{+}

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{I C I}_{4}^{-}

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{S F}_{4}

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{X e F}_{4}

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Solution

The correct option is C ${S F}_{4}$
$S F_{4}$
Stearic No. $= \frac{6 + 4}{2} = 5$
Geometry $\to$ Trigonal Bipyramidal
Hybridisation $\to s p^{3} d^{2}$

From the figure, we can say
No. of bond pair $= 4$
No. of lone pair $= 1$

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Similar questions

The number of lone pairs of electrons on SF₄, CF₄ and XeF₄are:

S F_{4}

C F_{4}

X e F_{4}

{B F_{4}}^{-}

S F_{4}, C F_{4}

X e F_{4}

S F_{4}

X e O_{4}

X e F_{4}

I C l_{4}^{-}

Which one of the following compounds has 2 lone pairs?

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