Which of the following compound is expected to have the highest boiling point?
$P H_{3}, N H_{3}, (C H_{3})_{3} N$

N H_{3}

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(C H_{3})_{3} N

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P H_{3}

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None of these

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Solution

The correct option is A $N H_{3}$
The trend of boiling point sholud increase with size but even though $N H_{3}$ is smaller than $P H_{3}$ , it has higher boiling point due to the high charge ratio on nitrogen and mainly, because of hydrogen bonding interactions. A hydrogen bond is the electrostatic attraction between polar groups that occurs when a hydrogen $(H)$ atom bound to a highly electronegative atom such as nitrogen $(N)$ , oxygen $(O)$ or fluorine $(F)$ experiences attraction to some other nearby highly electronegative atom.

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Similar questions

P H_{3} + \oplus N H_{4} ⟶ \oplus P H_{4} + N H_{3}

N H_{3} + P {\oplus H}_{4} ⟶ N {\oplus H}_{4} + P H_{3}

(C H_{3})_{3} P + \oplus N H_{4} ⟶ (C H_{3})_{3} \oplus P H + N H_{3}

(C H_{3})_{3} N + P H_{4}^{\oplus} ⟶ (C H_{3})_{3} \oplus N H + P H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

The order of boiling point of $N H_{3}, H_{2} O, H F a n d P H_{3}$ is

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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