Question

Which of the following compound is having maximum number of atoms in same plane?

• A. $A{l}_{2}M{e}_6$
• B. $B_2{H}_6$
• C. $B{e}_2{H}_4$
• D. $C_3{H}_4$

Answer 1

The correct option is A $A{l}_{2}M{e}_6$

a) Structure of $A{l}_{2}M{e}_6$ is
Maximum number of atoms that can lie in the same plane are 10 ( 2 $Al$, 4 $C$ and 4 $H$ atoms).

b) Structure of $B_2{H}_6$ is:
So, maximum number of atoms that can lie same plane = 6 ( 2 $B$ atoms and 4 terminal hydrogen atoms)


c) Structure of $B{e}_2{H}_4$ is:

So, Number of atoms in same plane = 6 ( 2 $Be$ atoms and 4 hydrogen atoms).

d) Stucture of $C_3{H}_4$ is:

It is called as allene with even number of $\pi$ bonds and thus is not planar. The two hydrogens are in the plane and other two are above and below the plane.
So, Number of atoms in same plane = 5 ( 3 carbon atoms and 2 hydrogen atoms)