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B
CH3C=CC|ClCOOH; 2-methylhex-3-enoic acid
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C
CH3CH2CH=CHCOCH3; hex-3-en-2-one
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D
H3CC|H3CHCH2CH2CHO; 4-methylpentanal
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Solution
The correct option is BCH3C=CC|ClCOOH; 2-methylhex-3-enoic acid The correct IUPAC name of compound in option B is 2-chloropent-3-enoic acid. The parent compound is pentanoic acid. A double bond is present between third and fourth carbon atoms. Chlorine group is present at second carbon atom.