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Question

Which of the following compound(s) terminal (2c2e) bonds and bridge bonds are lying in same plane?

A
I2Cl6
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B
Fe2Cl4
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C
Solid BeCl2
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D
Ga2H6
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Solution

The correct options are
A I2Cl6
B Fe2Cl4
a) ICl3 dimerizes to give I2Cl6 in which two Cl atoms are bridged and donate their lone pair to I atoms resulting in a 3C4e bond known as bridged bonding, whereas four Cl are bonded to I via 2C2e bond known as terminal bonds. So each I has two lone pairs and four σ bond pairs, i.e. sp3d2 hybridised and has octahedral geometry around it. Therefore, Cl atoms along with I lies in the same plane.
b) In Fe2Cl4, two Cl atoms are bonded with Fe via 2C2e bond which are called terminal Cl, while the other two Cl are bonded with Fe via 3C4e bond in which the Cl atom donates its lone pair to the vacant d orbitals of Fe also known as bridged atoms. Terminal as well as bridged atoms lies in the same plane of Fe.c) In solid state, BeCl2 polymerises to give (BeCl2)n. In polymeric chain each Be is tetrahedrally surrounded by Cl atoms, two bridged Cl atoms lies in same plane of Be and other two bridged Cl atoms lies above and below this plane i.e perpendicularly. So, two Cl falls in same plane of Be and other two Cl atoms are above and below this plane.
d) In Ga2H6 each Ga is sp3 hybridized and is tetravalent. So, twoHlies in the same plane and other two atoms lies above and below the plane as shown.

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