Which of the following compounds are expected to the covalent?

B e C l_{2}

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S n C l_{4}

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C u S

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C a C l_{2}

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Solution

The correct options are
A $B e C l_{2}$
B $S n C l_{4}$
The oxidation state of $B e$ and Sn in $B e C l_{2}$ and $S n C l_{4}$ are $+ 2$ and $+ 4$ respectively. Due to small size of cations the polarizing power of the cations is very high. CuS is not covalent because Cu does not have pseudo stable inert gas configuration : $2, 8, 18$ .

Suggest Corrections

Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2}

M g C l_{2}

C a C l_{2}

B e

[A g = 47, C u = 29, M g = 12]

A l F_{3}

A l C l_{3}

M g C l_{2}

B e C l_{2}

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