Which of the following compounds are paramagnetic in nature?

K O_{2}

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K_{2} O_{2}

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{N a}_{2} O_{2}

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R b O_{2}

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Solution

The correct options are
A $K O_{2}$
D $R b O_{2}$
Concept:If the number of electrons is odd, then the molecule is usally paramagnetic - If the electrons are unpaired.Concept:If the number of electrons is even, then the molecule is usally diamagnetic - If all the electrons are paired.
A) $K O_{2}$ (19+28=35,odd electrons) so paramagnetic.
B) $K_{2} O_{2}$ (219+28=54 even electrons) so diamagnetic.
C) ${N a}_{2} O_{2}$ (211+28=38 even electrons) so diamagnetic.
D) $R b O_{2}$ (37+28=43 odd electrons) so paramagnetic.
Hence options A & D are correct.

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