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Question

Which of the following compounds are paramagnetic in nature?

A
KO2
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B
K2O2
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C
Na2O2
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D
RbO2
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Solution

The correct options are
A KO2
D RbO2
Concept:If the number of electrons is odd, then the molecule is usally paramagnetic - If the electrons are unpaired.Concept:If the number of electrons is even, then the molecule is usally diamagnetic - If all the electrons are paired.
A) KO2(19+2*8=35,odd electrons) so paramagnetic.
B) K2O2(2*19+2*8=54 even
electrons) so diamagnetic.
C) Na2O2(2*11+2*8=38 even electrons) so diamagnetic.
D) RbO2 (37+2*8=43 odd electrons) so paramagnetic.
Hence options A & D are correct.


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