Question

Which of the following compounds exhibits geometrical iosmerism?

• A. $C_2{H}_{5}Br$
• B. $\left(CH{)}_2\right(COOH{)}_2$
• C. $C{H}_{3}CHO$
• D. $\left(C{H}_2{)}_2\right(COOH{)}_2$

Answer 1

The correct option is B $\left(CH{)}_2\right(COOH{)}_2$

Geometrical Isomerism arises due to different arrangement atoms/groups around a system where free rotation of bonds is restricted. Free rotation of bonds can be restricted by double bonds. π-bond gives rigidity to molecule, the rotation around the double bond is prevented. The restriction in free rotation makes the position of groups attached to $s{p}^2$ hybrid C fixed into space.

$\left(CH{)}_2\right(COOH{)}_2$ is $HOOC-CH=CH-COOH$, hence here geometrical isomerism is possible.