Which of the following compounds has all carbon atoms in $s p$ hybridized state?

C H_{3} - C H_{2} - C H_{2} - C H_{3}

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H - C \equiv C - C \equiv C H

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C H_{3} - C H = C H - C H_{3}

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None of these

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Solution

The correct option is C $H - C \equiv C - C \equiv C H$
In $H - C \equiv C - C \equiv C - H$ , all the carbon atoms form only 2 $σ$ bonds and thus are $s p$ hybridised.

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Similar questions

What are the hybridization states of each carbon atom(s) in the following molecules ?

(i) $C H_{3} * C H_{2} C H_{2} C H_{3}$

(ii) $C H_{2} = C^{*} H - C H = C H_{2}$

(iii) $C H_{3} * C H = C H - C H_{3}$

(iv) $H - * C \equiv C - H$

Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

and

C H \equiv C H

is:

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

Q. IUPAC name of given compound:

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

Q. Which amongst the following is a positional isomer of

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

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Which of the following compounds has all carbon atoms in sp hybridized state?

The correct option is C H−C≡C−C≡CHIn H−C≡C−C≡C−H, all the carbon atoms form only 2 σ bonds and thus are sp hybridised.

Which of the following compounds has all carbon atoms in $s p$ hybridized state?

The correct option is C $H - C \equiv C - C \equiv C H$
In $H - C \equiv C - C \equiv C - H$ , all the carbon atoms form only 2 $σ$ bonds and thus are $s p$ hybridised.