Which of the following compounds have same percentage composition of carbon?

C_{6} H_{12} O_{6}

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C H_{3} C O O H

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H C O O C H_{3}

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C_{12} H_{22} O_{11}

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Solution

The correct option is A $C_{6} H_{12} O_{6}$
In $C_{6} H_{12} O_{6}$ we have molecular weight = 180
percentage of carbon = $\frac{m a s s o f c a r b o n * 100}{m o l e c u l a r m a s s}$

percentage of carbon = 40
in $C H_{3} C O O H$ , molcular mass = 60 and percentage of carbon = 40

in $H C O O C H_{3}$ , molecular weight = 60, percentage of carbon= 40

in $C_{12} H_{22} O_{11}$ , molecular weight = 342, percentage of carbon = 42.15

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