Which of the following compounds have zero oxidation state at carbon?

C_{6} H_{12} O_{6}

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HCOOH

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HCHO

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C H_{4}

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Solution

The correct options are
A $C_{6} H_{12} O_{6}$
C HCHO
Oxidation number of carbon in $C_{6} H_{12} O_{6}$ = $\frac{2 \times 6 - 12}{6} = 0$
Oxidation number of carbon in $H C O O H$ = $\frac{2 \times 2 - 2}{1} = + 2$
Oxidation number of carbon in $H C H O$ = $\frac{2 \times 1 - 2}{1} = 0$
Oxidation number of carbon in $C H_{4}$ = $\frac{2 \times 0 - 4}{1} = - 4$

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