The correct options are
A (CH3)2CHCH2OH
B CH3CH2OH
D CCl2F2
The compounds (CH3)2CHCH2OH, CH3CH2OH and CCl2F2 do not have any chiral center. So, they are optically inactive in nature.
The compound CH3∗CH(OH)C2H5 has a chiral center (starred carbon) and so is optically active.