Question

Which of the following compounds may not exist as enantiomers?

• A. $\text{C}{\text{H}}_{\text{3}}\text{CH}\left(\text{OH}\right)\text{C}{\text{O}}_{\text{2}}\text{H}$
• B. $\text{C}{\text{H}}_{\text{3}}\text{C}{\text{H}}_{\text{2}}\text{CH}\left(\text{C}{\text{H}}_{\text{3}}\right)\text{C}{\text{H}}_{\text{2}}\text{OH}$
• C. ${\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{C}{\text{H}}_{\text{2}}\text{C}{\text{H}}_{\text{3}}$
• D. ${\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{CHClC}{\text{H}}_{\text{3}}$

Answer 1

Answer: (C)

${\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{C}{\text{H}}_{\text{2}}\text{C}{\text{H}}_{\text{3}}$

It has no chiral centre so, it cannot exist as enantiomers. It should have four different group on carbon bearing enantiomeric center.