Which of the following compounds represent represent a normal $2 : 3$ spinel structure?

M g^{I I} A l_{2}^{I I I} O_{4}

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C o^{I I} (C o^{I I I})_{2} O_{4}

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Z n (T i Z n) O_{4}

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N i (C O)_{4}

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Solution

The correct options are
A $C o^{I I} (C o^{I I I})_{2} O_{4}$
C $M g^{I I} A l_{2}^{I I I} O_{4}$
In $2 : 3$ spinel structure General formula is $A^{+ 2} B_{2}^{+ 3} O_{4}$
$A^{+ 2} : \frac{1}{8} \times T e t r a h e d r a l v o i d s$ $B^{+ 3} : \frac{1}{2} \times O c t a h e d r a l v o i d s$ $O^{2 -} : F C C l a t t i c e$

Only $M g^{+ 2} A l_{2}^{+ 3} O_{4}$ and $C o^{2 +} (C o^{3 +})_{2} O_{4}$ satisfies the above conditions.

$⟶$ Also, in option (C) $T i$ have $+ 4$ oxidtion state.

Ans-(A), (B)

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