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Geometrical Isomerism

Which of the ...

Question

Which of the following compounds show geometrical isomerism?

C H_{3} - C H = C C l_{2}

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C H_{3} - C H = C H_{2}

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(C H_{3})_{2} - C = C H_{2}

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C H_{3} - C C l = C C l - C H_{3}

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Solution

The correct option is D $C H_{3} - C C l = C C l - C H_{3}$
Compounds containing $x y C = C x y$ type or $a b C = C x y$ type structure show geometrical isomerism.
Hence $C H_{3} - C C l = C C l - C H_{3}$ compound shows cis and trans form of geometrical isomerism.

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Similar questions

{C H}_{3} C H_{2} {C H}_{2} {C H}_{2} {C H}_{3}, {C H}_{3} - {C H}_{3} | C H - {C H}_{2} C H_{3}, {C H}_{3} - {C H}_{3} | C_{3} - {C H}_{3}

{C H}_{3} - {C H}_{2} - C | H - C H_{2} C H_{3} C H_{2} - C | H C H_{3} - C H_{2} - C H_{3}

C H C l = C H C l, C H_{2} = C C l_{2}, a n d C C l_{2} = C H C l .

C H_{3} - C \equiv C - C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H_{2} C \equiv C H

C H_{3} - C H = C H_{2}

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