Question

Which of the following compounds will give only one isomer on monochlorination

(i)Isopentane (ii) Neopetane (iii) Cyclopentane (iv) 2,2,3,3 - tetramethyl butane (v) n-butane

• A. i and ii only
• B. (ii) & (iii) only
• C. (ii) & (iv) only
• D. (ii), (iii)& (iv)

Answer 1

The correct option is D

(ii), (iii)& (iv)

$C{H}_3-\underset{C{H}_3}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-C{H}_3$(Neo pentane) (Cyclopentane)

$H_{3}C-\underset{C{H}_3}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{C{H}_3}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-C{H}_3$ (2,2,3,3-tetra methyl butane)

Give only one isomer on monochlorination as they have only one type of hydrogen.