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Liquefaction

Which of the ...

Question

Which of the following conditions is favourable for liquefaction of gas?

A

T > T_{c}; P > P_{c}

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B

T < T_{c}; P > P_{c}

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C

T = T_{c}; P = P_{c}

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D

T = T_{c}; P < P_{c}

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Solution

The correct option is B $T < T_{c}; P > P_{c}$
The following conditions are favourable for liquefaction of gas:

$T < T_{c}$ and $P > P_{c}$

The temperature is less than critical temperature and the pressure is less more than critical pressure. A gas may be liquefied by cooling or by the application of high pressure or by the combined effect of both. A gas can be liquefied by pressure if it is at or below its critical temperature.

Hence, option B is correct.

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Similar questions

\frac{P}{P_{c}} = x

(reduced pressure),

\frac{V}{V_{c}} = y

(reduced volume) and

\frac{T}{T_{c}} = z

(reduced temperature), then,

Q. The vander waal's equation of corresponding states for 1 mole of gas is [where

P_{c} =

critical pressure,

T_{c} =

critical temperature,

V_{c} =

critical volume]

[π = \frac{P}{P_{c}}, ϕ = \frac{V}{V_{c}} a n d θ = \frac{T}{T_{c}}]

\frac{P}{P_{c}} = P_{r}, \frac{T}{T_{c}} = T_{r}, a n d \frac{V_{m}}{V_{m, c}} = V_{r}

P_{r}

is reduced pressure,

P_{c}

is critical pressure

T_{r}

is reduced temperature,

T_{c}

is critical temperature

V_{r}

is reduced volume,

V_{c}

is critical volume
then the equation of state (or van der Waals equation), only in terms of

P_{r}, T_{r}

V_{r}

N O

C C l_{4}

, the values of

P_{c}

T_{c}

are given below:

Molecules	$T_{c}$	$P_{c}$
$N O$	177 K	6.485 atm
$C C l_{4}$	550 K	4.56 atm

Select the correct statement(s).

Q. The relationship between

P_{c}, V_{c}

T_{c}

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