Which of the following conditions support the formation of an ionic bond?

Low ionisation energy of the metal atom

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Low ionisation energy of the non-metal atom

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Positive electron gain enthalpy of the metal atom

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Negative electron gain enthalpy of the non-metal atom

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A Low ionisation energy of the metal atom
D Negative electron gain enthalpy of the non-metal atom
Ionic bond is formed by complete transfer of electrons from a metal atom to a non-metal atom.
Conditions for forming an ionic bond are:

Metal atom should have low ionisation energy so that it can easily donate its electron(s).

Non-metal atom should have high negative value of electron gain enthalpy which represents stronger hold on the gained electron(s).

Suggest Corrections

Similar questions

Match the corect ionisation enthalpies and electron gain enthalpies of the following elements.
$\begin{matrix} E l e m e n t s & △ H_{1} & △ H_{2} & △_{e g} H (i) & M o s t r e a c t i v e n o n m e t a l & A & 419 & 3051 & - 48 (i i) & M o s t r e a c t i v e m e t a l & B & 1681 & 3374 & - 328 (i i i) & L e a s t r e a c t i v e e l e m e n t & C & 738 & 1451 & - 40 (i v) & M e t a l f o r m i n g b i n a r y h a l i d e & D . & 2372 & 5251 & + 48 \end{matrix}$

Assertion: The greater the ionisation energy the greater the non-metallic character.

Reason: Metals are electron accepting and non-metals are electron donating.

Q. Define: Atomic radius, Ionic radius, Ionisation Enthalpy, Electron Gain enthalpy, Electronegativity.

Q. Ionisation enthalpy of an atom is equal to :-
1. Electron gain enthalpy of the cation.
2. Electronegativity of the ion.
3. Ionisation enthalpy of the cation.
4. Electron gain enthalpy of anion.

Q. Ionisation energy of

F^{-}

320 k J m o l^{- 1}

. The electron gain enthalpy of fluorine would be:

Join BYJU'S Learning Program