Which of the following contains greatest number of $N$ atoms?

22.4 L

nitrogen gas at

S T P

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500 m L o f 2.00 M N H_{3}

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1.00 m o l o f N H_{4} C l

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6.02 \times 10^{23} m o l e c u l e s o f N O_{2}

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Solution

The correct option is A $22.4 L$ nitrogen gas at $S T P$
According to basics of mole concept,

$a . 22.4 L N_{2} g a s a t S T P = 1 m o l N_{2}$

$= N_{0} m o l e c u l e s o f N_{2}$

$= 2 N_{0} a t o m s o f N$

$b . \frac{500 \times 2}{1000} = 1 m o l o f N H_{3}$

$= N_{0} m o l e c u l e s o f N H_{3}$

$= N_{0} a t o m s o f N$

$c . 1 m o l o f N H_{4} C l = N_{0} a t o m s o f N$

$d . 6.02 \times 10^{23} N O_{2} m o l e c u l e s = 6.02 \times 10^{23} a t o m s o f N = N_{0} a t o m s o f N$

So $22.4 L$ nitrogen gas at $S T P$ have maximum no. of $N$ atoms.

Hence, the correct option is $A$

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Which sample contains the greatest number of nitrogen atoms? (All measurements are taken at STP.)

6.02 \times 10^{23}

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= 22.4 L

S T P

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