Question

Which of the following contains the largest number of oxygen atoms?

1.0 g of $O$ atoms, 1.0 g of $O_2$, 1.0 g of ozone $O_3$.

• A. 1 g of $O$
• B. 1 g of $O_2$
• C. 1 g of $O_3$
• D. All have same number of atoms

Answer 1

The correct option is D All have same number of atoms

Atomic ass of O atom $=16g$

Number of atoms in $10g$ of O atoms $=6.023\times {10}^{23}$

So, Number of atoms in 1 g of O atom $=\frac{6.023\times {10}^{23}}{16}$

$=0.376\times {10}^{23}$ atoms.

Molecular mass of $O_2=32g$

Number of atoms in 32 g of $O_2$ $=2\times 6.023\times {10}^{23}$

So, number of atoms in 1 g of $O_2$$=\frac{2\times 6.023\times {10}^{23}}{32}\times 1=0.376\times {10}^{23}$atoms.

The molecular mass of $O_2=48g$

Number of atoms in $48g$of $O_2$ $=3\times 6.023\times {10}^{23}$

So, number of atoms n 1g of $O_3=\frac{3\times 6.023\times {10}^{23}}{48}\times 1$

$=0.376\times {10}^{23}$ atoms.

Hence All have the same numbers of atoms.

Hence, the correct option is $\text{D}$