Question

Which of the following contains the same number of atoms as in there are in $2.4$ g of carbon?

• A. $0.1$ moles of Oxygen
• B. $2.8$ g of Nitrogen
• C. $2$ g of Hydrogen
• D. $35.5$ g of Chlorine

Answer 1

Answer: (A), (B)

$2.8$ g of Nitrogen
$0.1$ moles of Oxygen

No. of atoms in $2.4$ g of C = $\frac{6.02\times {10}^{23}\times 2.4}{12}=1.2\times {10}^{23}$
A) $0.1$ moles of Oxygen:
No. of atoms = $2\times 6.02\times {10}^{23}\times 0.1$ = $1.2\times {10}^{23}$
B) $2.8$ g of Nitrogen:
No. of atoms = $\frac{2\times 6.02\times {10}^{23}\times 2.8}{28}$ =$1.2\times {10}^{23}$
C) $2$ g of Hydrogen:
No. of atoms = $6.02\times {10}^{23}$
D) $35.5$ g of Chlorine:
No. of atoms = $\frac{6.02\times {10}^{23}\times 35.5}{71}=3.01\times {10}^{23}$
Therefore $0.1$ moles of Oxygen and $2.8$ g of Nitrogen has same no. of atoms as in $2.4$ g of carbon.