Which of the following correctly explains distributive law?

$a \times (b + c) = b \times a + a \times c$

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$b \times (a + c) = b \times a + b \times c$

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$(a + c) \times b = a \times b + c \times b$

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All of these

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Solution

The correct option is D
All of these

All the above options shows distributivity of multiplication over addition i.e. $x \times (y + z) = x \times y + x \times z$ . This is known as distributive law.

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Similar questions

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + c b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3 (b - c) (c - a) (a - b) (a + b + c) (b c + c a + a b)

\frac{a^{3} (b + c)}{(a - b) (a - c)} + \frac{b^{3} (c + a)}{(b - c) (b - a)} + \frac{a^{3} (a + b)}{(c - a) (c - b)} = b c + c a + a b

a, b, c

{(\frac{a + c}{a - c})}^{a} < {(\frac{b + c}{b - c})}^{b}

\sum_{a, b, c} (b - c) (b + c)

{(\sum_{a, b, c} a)}_{a, b, c}^{2} - (\sum_{a, b, c} a^{2})

\sum_{a, b, c} (a + 1)^{3} (b^{2} - c^{2})

A \cap (B - C) = (A \cap B) - (A \cap C)

A \cap (B - C) = (A \cap B) - C

A \cup (B - C) = (A \cup B) \cap (A \cup C')

A \cup (B - C) = (A \cup B) - (A \cup C) .

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