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Question

Which of the following correctly represent solubility of N2 in water (in terms of mmole/litre) if N2 is bubbled through water at 293 K at a pressure of 0.768 bar and Henry's constant is 76.8 K at 293 K?

A
105
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B
5.56×104
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C
102
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D
4.3×104
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Solution

The correct option is A 105
According to Henry's Law
PN2=KM×HN2
HN2=0.768×10
76.8×102×103
=105
H_{N_2}=HN_2$
n values
105=NO255.55
NO2=55.55×105mole
Concentration of N2
=5.56×101
=1555.4×1
=1.0015544

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