Which of the following covalent molecule is an exception to octet rule?

B e C l_{2}

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C O_{2}

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H_{2} O

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C H_{4}

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Solution

The correct option is A $B e C l_{2}$
In $B e {C l}_{2}$ , the octet is incomplete because $B e$ has $2$ valence electrons of its own and after bonding with $2 C l$ atoms, it gains two more electrons. Hence, it has a total of $4$ electrons which is less than $8$ . Hence its octet is incomplete.

Option A is the correct answer.

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Similar questions

How many covalent bonds are present in the following compounds?

(i) $C O_{2}$

(ii) $H_{2} O$

(iii) $C H_{4}$

(iv) $N_{2}$

(v) $N H_{3}$

Q. Amongst

N H_{3}, B e C l_{2}, C O_{2}

H_{2} O

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