Which of the following decolourises alkaline $K M n O_{4}$ solution?

C_{3} H_{8}

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C_{2} H_{4}

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C H_{4}

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C C l_{4}

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Solution

The correct option is C $C_{2} H_{4}$
$C_{2} H_{4}$ decolorizes alkaline $K M n O_{4}$ solution.
Alkaline $K M n O_{4}$ (Bayers reagent) oxidizes ethylene to ethylene glycol and itself is reduced to $M n O_{2}$ .
$C_{2} H_{4} + H_{2} O + [O] \to C H_{2} O H - C H_{2} O H$

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