Which of the following diatomic molecules/ion having same bond order?

O_{2}

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C N^{-}

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N_{2}

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C_{2}

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Solution

The correct options are
B $C N^{-}$
D $N_{2}$
Both nitrogen and cyanide ion have $14$ electrons.

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Similar questions

Q. Which of the following molecules/species have identical bond order and same magnetic properties?

(I)

O_{2}

(II)

N O

(III)

N_{2}^{+}

Calculate the total number of molecules that will possess fractional bond order among the following molecules
$O_{2}^{2 +}, N_{2}^{2 +}, O_{2}^{+}, N O, C O, C O^{+}, O_{2}^{-}, N O^{2 +}, C N^{-}, N O^{2 -}, N_{2}^{-}$

Q. Which of the following have identical bond order?

(

C N^{-}, O_{2}^{-}, N O^{+}, C N^{+}

)

Q. Number of paramagnetic molecules from the following are:

C N^{-}, N O, O_{2}^{2 -}, O_{2}, N O_{2}, O_{2}^{-}, B_{2}, C_{2}, F_{2}^{-}

Q. Assertion :

O_{2}

molecule is diamagnetic while

C_{2}

molecule is paramagnetic in nature. Reason: Bond order of

O_{2}

molecule is 1.5 and that of

C_{2}

molecule is 2.5.

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Which of the following diatomic molecules/ion having same bond order?

The correct options are B CN− D N2Both nitrogen and cyanide ion have 14 electrons.

The correct options are
B $C N^{-}$
D $N_{2}$
Both nitrogen and cyanide ion have $14$ electrons.