Which of the following disproportinate(s) on heating with sodium hydroxide?

P_{4}

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S_{8}

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C l_{2}

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B

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Solution

The correct options are
A $S_{8}$
B $C l_{2}$
C $P_{4}$
In disproportianation reaction, one of the species in the reaction undergo oxidation and reduction simultaneously.

$P_{4}, S_{8},$ and $C l_{2}$ undergo disproportionation reaction. Their reaction can be given as following:

(A) $P_{4} + 3 N a O H + 3 H_{2} O \to P H_{3} + 3 N a H_{2} P O_{2}$

(B) $4 S + 6 N a O H Δ - \to N a_{2} S_{2} O_{3} + 2 N a_{2} S + 3 H_{2} O$

(C) $3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

Only $B o r o n$ does not undergo disproportionation reaction.

(D) $2 B + 6 N a O H \to 2 N a_{3} B O_{3} + 3 H_{2}$ .

Option A, B and C are correct.

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C l_{2}

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