Which of the following does not contain any coordinate bond?

H_{3} O^{+}

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B F_{4}^{-}

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H F_{2}^{-}

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N H_{4}^{+}

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Solution

The correct option is C $H F_{2}^{-}$
$H_{3} O^{+}$ has one coordinate bond formed using the empty orbital of $H^{+}$ and the lone pair of oxygen atom (in $H_{2} O)$ .

$B F_{4}^{-}$ forms a coordinate bond using the empty $2 p$ orbital of $B$ in $B F_{3}$ and the lone pair of $F^{-}$ .

$H F_{2}^{-}$ does not have any coordinate bond

In $N H_{4}^{+}$ , the lone pair on nitrogen (in $N H_{3})$ forms coordinate bond with $H^{+}$ . $N$ donates its lone pair to the vacant orbital of $H^{+}$ .

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B F_{3} + F^{-} \to B F_{4}^{-}

H F + S b F_{5} \to H S b F_{6}

P C l_{3} + C l^{-} \to P C l_{4}^{-}

N H_{3} + H^{+} \to N H_{4}^{+}

H_{3} O + H^{+} \to H_{4} O^{+}

Which of the following conversions involve change in both shape and hybridisation?

a) CH4 -> C2H6

b) NH3 -> NH4+

c) BF3 -> BF4-

d) H2O ->H3O+

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