Question

Which of the following does not have a pseudo noble gas configuration?

• A. $Z{n}^{2+}$
• B. $S{n}^{4+}$
• C. $A{l}^{3+}$
• D. $I{n}^{3+}$

Answer 1

The correct option is C $A{l}^{3+}$

When a d block element loses its outermost s orbital electrons and in turn, the whole s sub shell, it is said to have a pseudo noble gas configuration.
$Z{n}^{2+}$=$\left[Ar\right]3d^{10}4s$ loses all its electrons
$S{n}^{4+}$=$\left[Kr\right]4d^{10}5s$ and $5p$ lose all their electrons
$A{l}^{3+}$=$\left[Ne\right]$
$I{n}^{3+}$=$\left[Kr\right]4d^{10}5s$ and $5p$ lose all their electrons

So $A{l}^{3+}$ has a regular noble gas configuration and is the answer here.