The correct option is C Al3+
When a d block element loses its outermost s orbital electrons and in turn, the whole s sub shell, it is said to have a pseudo noble gas configuration.
Zn2+=[Ar]3d10 4s loses all its electrons
Sn4+=[Kr]4d10 5s and 5p lose all their electrons
In3+=[Kr]4d10 5s and 5p lose all their electrons
So Al3+ has a regular noble gas configuration and is the answer here.