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Standard XII

Chemistry

Heat of Reaction

Which of the ...

Question

Which of the following does not have zero value of standard enthalpy of formation?

C_{g r a p h i t e}

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H_{2} (g)

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O_{2} (g)

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H C l (g)

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Solution

The correct option is C $H C l (g)$
Solution:- (D) $H C l - (g)$
As we know that the standard enthalpy of formation for an element in its elemental state will always be $0$ .
Hence ${H C l}_{(g)}$ will not have zero value of standard enthalpy of formation.

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Similar questions

Q. Calculate the standard enthalpy of formation of

C H_{3} O H (I)

from the following data :

C H_{3} O H (I) + \frac{3}{2} O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l); △_{r} H^{θ} = - 726 k J m p l^{- 1}

C_{(g r a p h i t e)} + O_{2} (g) \to C O_{2} (g); △_{c} H^{θ} = - 393 k J m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); △_{f} H^{θ} = - 286 k J m o l^{- 1}

C H_{3} O H (1) + \frac{3}{2} O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (I); Δ, H^{⊖} = - 726 k J m o l^{- 1}

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g); Δ_{c} H^{⊖} = - 393 k J m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (I); Δ_{f} H^{⊖} = - 286 k J m o l^{- 1}

Calculate the standard enthalpy of formation of

{C H}_{3} O H (l)

from the following data:

Q. Calculate the standard enthalpy of formation of

C H_{3} O H (l)

from the following data.

C H_{3} O H (l) + \frac{3}{2} O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)

;

Δ H^{o} = - 726

m o l^{- 1}

C(graphite)

+ O_{2} (g) \to C O_{2} (g);

Δ_{c} H^{0} = - 393

m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l);

Δ_{t} H^{o} = - 286

m o l^{- 1}

Q. Calculate enthalpy for formation of ethylene from the following data:

(I)

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g); Δ H = - 393.5 k J

(II)

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = - 286.2 k J

(III)

C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l); Δ H = - 1410.8 k J

The molar enthalpies of combusion of $C_{2} H_{2 (g)}$ , $C_{(g r a p h i t e)}$ and $H_{2 (g)}$ are -1300,-394,-286 kJmol $^{- 1}$ respectively. The standard enthalpy of formation of $C_{2} H_{2 (g)}$ is

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Which of the following does not have zero value of standard enthalpy of formation?

The correct option is C HCl(g)Solution:- (D) HCl−(g)As we know that the standard enthalpy of formation for an element in its elemental state will always be 0.Hence HCl(g) will not have zero value of standard enthalpy of formation.

The correct option is C $H C l (g)$
Solution:- (D) $H C l - (g)$
As we know that the standard enthalpy of formation for an element in its elemental state will always be $0$ .
Hence ${H C l}_{(g)}$ will not have zero value of standard enthalpy of formation.