The correct option is D Decrease in relative density of electrolyte
Lead Storage Battery:-
When the battery discharge,
At anode: Pb(s)+SO2−4(aq)→PbSO4(s)+2e−
Most of the lead sulphate precipitates formed gets sticks to the lead rod. Thus, it is not consumed during discharging.
At cathode: PbO2(s)+SO2−4(aq)+4H+(aq)+2e−→PbSO4(s)+2H2O(l)
Here also formed lead sulphate precipitate gets sticks
to cathode rod.
Overall reaction during discharge:
Pb(s)+PbO2(s)+2H2SO4(aq)→2PbSO4(s)+2H2O(l)
Ecell=2.05 V
H2O is produced in the cell reaction.
H2SO4 is consumed in the cell reaction during discharge. So, its concentration in the solution decreases and results in decrease in the density of the solution.
On charging the lead storage battery, the reactions are reversed
and produce H2SO4
At anode: PbSO4 gets converted
into Pb
At cathode: PbSO4 gets converted into PbO2
Cell reaction:
2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq)
H2SO4 is produced in the cell reaction during charging. So, its concentration in the solution increases and results in increase in the density of the solution.