You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ionisation Energy

Which of the ...

Question

Which of the following electronic configuration corresponds to an element having the lowest $1 s t$ ionization energy?

1 s^{2} 2 s^{2} 2 p^{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 s^{2} 2 s^{2} 2 p^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s^{2} 2 s^{2} 2 p^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
The $s$ -block elements have low ionization potential as compared to $p$ -block elements because $s$ -block elements easily lose $1$ electron to get the stable configuration of noble elements while $p$ -block elements gain electrons to get their stable octet configuration.
Hence, option B is correct.

Suggest Corrections

Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{3}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

1 s^{2} 2 s^{2} 2 p^{3}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

A, B, C

D

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1^{s t}

2^{n d}

A = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

B = 1 s^{2} 2 s^{2} 2 p^{5}

Join BYJU'S Learning Program