Which of the following electronic configuration is not possible?

2 p^{6}

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3 s^{1}

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2 p^{5}

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3 f^{12}

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Solution

The correct option is D $3 f^{12}$
The electronic configuration $3 f^{12}$ is not possible as third energy level can have s,p and d orbitals only. For f orbital, $l = 3$ . But for third energy level $n = 3$ and $= l = 0, 1, 2$ as l can have values 0 to $n - 1$ .

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s^{2}

s^{2}

p^{6}

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1 s^{2} 2 s^{2} 2 p^{6} {3 s}^{1}

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[N e] 3 s^{1}

Element	Subshell electronic configuration	No. of electrons present in the last subshell	Group number
$L i$	$1 s^{2} 2 s^{2}$	$1$	$1$
$N a$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$	-	$1$
$M g$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$	-	$2$
$C a$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 s^{2} 3 p^{6} 4 s^{2}$	-	-

[N e] 3 s^{1}

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