Which of the following electronic configuration represents neon?

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

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1 s^{2} 2 s^{2} 2 p^{6}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

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Solution

The correct option is C $1 s^{2} 2 s^{2} 2 p^{6}$
The atomic number of neon is 10. Thus, it has 10 electrons.
While writing the electron configuration for neon the first two electrons are filled in the 1s orbital. Since, 1s can only hold two electrons the next 2 electrons are filled in the 2s orbital. The remaining six electrons are filled in the 2p orbital. Therefore, the Ne electron configuration will be
$1 s^{2} 2 s^{2} 2 p^{6}$ .

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Similar questions

The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{2}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

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