The correct options are
A CH3.CHClCH2.CH3+NaOEtEtOH−−−→△
C CH3.CH2.CHCl.CH3+Me3CO−K+△→
In case of A & D, 2-butene is formed as product but in case of B & C, 1-butene formed as major product.
CH3.CHClCH2.CH3+NaOEtEtOH−−−→△CH3CH=CHCH3
CH3.CH2.CHCl.CH3+Me3CO−K+△→CH3CH=CHCH3