Which of the following equation has infinitely many solutions?

2 x + 5 = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x + 5 y = x - 5 y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 x + 3 = y + 6 x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y - 4 = 4 - y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 x + 5 y = x - 5 y$
On simplifying, $2 x + 5 = 3$ we get, $x = - 1$
$\Rightarrow$ it has only one solution.
On simplifying, $2 x + 5 y = x - 5 y$ we get, $x = - 10 y$
$\Rightarrow$ on changing value of y value of x will also change so it has infinite solutions.
On simplifying, $6 x + 3 = y + 6 x$ we get, $y = 3$
$\Rightarrow$ it has only one solution.
Similarly, $y - 4 = 4 - y$ can be simplified to $y = 4$
$\Rightarrow$ it has only one solution.

Suggest Corrections

Similar questions

Q. Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions.
(i)

x - 3 y - 3 = 0; 3 x - 9 y - 2 = 0

(ii)

2 x + y = 5; 3 x + 2 y = 8

(iii)

3 x - 5 y = 20; 6 x - 10 y = 40

(iv)

x - 3 y - 7 = 0; 3 x - 3 y - 15 = 0

Q. The value of

k \in R,

for which the following system of linear equations

3 x - y + 4 z = 3,

x + 2 y - 3 z = - 2,

6 x + 5 y + k z = - 3,

has infinitely many solutions, is:

Q. For what value of k, the following pair of linear equation has infinitely many solutions?

10 x + 5 y - (k - 5) = 0 20 x + 10 y - k = 0

Which of the following pairs of linear equations has unique solution, no solution or infinitely many solutions? In case there is a unique solution, find it by using cross multiplication method.

Q. Solve the following equation:

\frac{5 y - 4}{8} - \frac{y - 3}{5} = \frac{y + 6}{4}

Join BYJU'S Learning Program