Which of the following equation is correct when excess of sodium hydroxide reacts with lead hydroxide?
A
Pb(OH)2+NaOH(excess)→2H2O+Na2PbO2
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B
Pb(OH)2+NaOH(excess)→H2O+Na2PbO2
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C
Pb(OH)2+2NaOH(excess)→2H2O+Na2PbO2
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D
Pb(OH)2+2NaOH(excess)→H2O+Na2PbO2
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Solution
The correct option is CPb(OH)2+2NaOH(excess)→2H2O+Na2PbO2 Pb(OH)2+2NaOH(excess)→2H2O+Na2PbO2 is correct when excess of sodium hydroxide reacts with lead hydroxide.