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Enthalpy

Which of the ...

Question

Which of the following equation is used to find the energy gained or lost during a particular phase change?

A

q = m c Δ T

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B

q = H_{V} m

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C

P_{1} V_{1} = P_{2} V_{2}

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D

D = m / V

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E

K = C + 273

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Solution

The correct option is A $q = H_{V} m$
The equation $q = H_{V} m$ is used to find the energy gained or lost during a particular phase change.
q is the energy gained or lost during a particular phase change.

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Similar questions

Q. Which gas law is summarized with the following equation?

P_{1} V_{1} = P_{2} V_{2}

Q. A thermodynamical system is changed from state

(P_{1}, V_{1})

(P_{2}, V_{2})

by two different processes. The quantity which will remain same will be:

For an ideal gas, an illustration of three different paths

A

(B + C)

(D + E)

from an initial state

P_{1}

V_{1}

T_{1}

to a final state

P_{2}

V_{2}

T_{1}

is shown in the given figure.
Path

A

represents a reversible Isothermal expansion from

P_{1}

V_{1}

P_{2}, V_{2}

(B + C)

reperesents a reversible adiabatic expansion

(B)

P_{1} V_{1}

T_{1}

P_{3}

V_{2}

T_{2}

followed by reversible heating the gas at constant volume

(C)

P_{3}

V_{2}

T_{2}

P_{2}

V_{2}

T_{1}

(D + E)

represents a reversible expansion at constant pressure

P_{1} (D)

P_{1}

V_{1}

T_{1}

P_{1}

V_{2}

T_{3}

followed by a reversible cooling at constant volume

V_{2} (E)

P_{1}

V_{2}

T_{3}

P_{2}

V_{2}

T_{1}

Δ S

(D + E) ?

n

moles of a perfect gas undergoes a cyclic process

A B C A

(see figure) consisting of the following processes -

A \to B

: Isothermal expansion at temperature

T

so that the volume is doubled from

V_{1}

V_{2}

and pressure changes from

P_{1}

P_{2}

B \to C

: Isobaric compression at pressure

P_{2}

to initial volume

V_{1}

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: Isochoric change, leading to change of pressure from

P_{2}

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.

Total work done in the complete cycle

A B C A

Q. Consider the following reversible cycle shown below.

It operates a diatomic gas. It's efficiency is given as If its now replaced by a monatomic gas then the change in percentage efficiency of the cycle is

η = \frac{γ - 1}{\frac{γ P_{2}}{P_{2} - P_{1}} + \frac{V}{V_{2} - V_{1}}}

Take P_{1} = 1 bar, P_{2} = 2 bar, v_{1} = 1 m^{3}, v_{2} = 2 m^{3}

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