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Standard VI

Mathematics

Solution of an Equation

: 7 Which of ...

Question

Question : 7

Which of the following equations has x = 2 as a solution?

(a) x + 2 = 5

(b) x - 2 = 0

(c) 2x + 1 = 0

(d) x + 3 = 6

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Solution

$\begin{matrix} Equation & Substituting x = 2 & Equation satisfied (a) x + 2 = 5 & 2 + 2 = 4 & N o (b) x - 2 = 0 & 2 - 2 = 0 & Y e s (c) 2 x + 1 = 0 & (2 \times 2) + 1 = 5 & N o (d) x + 3 = 6 & (2 + 3) = 5 & N o \end{matrix}$

$∴$ The equation x - 2 = 0 has x = 2 as solution.

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Similar questions

Q. Which of the following has q = 6 as the solution?

Question : 7

Which of the following equations has x = 2 as a solution?

(a) x + 2 = 5

(b) x - 2 = 0

(d) x + 3 = 6

Question 3
Which of the following equations has 2 as a root?
(a) $x^{2} - 4 x + 5 = 0$
(b) $x^{2} + 3 x - 12 = 0$
(c) $2 x^{2} - 7 x + 6 = 0$
(d) $3 x^{2} - 6 x - 2 = 0$

Q. Question 9
Which of the following equation has two distinct real roots?
(a)

2 x^{2} - 3 \sqrt{2} x + \frac{9}{4} = 0

(b)

x^{2} + x - 5 = 0

(c)

x^{2} + 3 x + 2 \sqrt{2} = 0

(d)

5 x^{2} - 3 x + 1 = 0

Q. Which of the following differential equations has y = C₁ e^x + C₂ e⁻^x as the general solution?
(a)

\frac{d^{2} y}{d x^{2}} + y = 0

(b)

\frac{d^{2} y}{d x^{2}} - y = 0

(c)

\frac{d^{2} y}{d x^{2}} + 1 = 0

(d)

\frac{d^{2} y}{d x^{2}} - 1 = 0

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Solution of an Equation

Standard VI Mathematics

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Question : 7 Which of the following equations has x = 2 as a solution? (a) x + 2 = 5 (b) x - 2 = 0 (c) 2x + 1 = 0 (d) x + 3 = 6

EquationSubstituting x = 2Equation satisfied(a)x+2=52+2=4No(b)x−2=02−2=0Yes(c)2x+1=0(2×2)+1=5No(d)x+3=6(2+3)=5No ∴The equation x - 2 = 0 has x = 2 as solution.

Question : 7

Which of the following equations has x = 2 as a solution?

(a) x + 2 = 5

(b) x - 2 = 0

(c) 2x + 1 = 0

(d) x + 3 = 6

$\begin{matrix} Equation & Substituting x = 2 & Equation satisfied (a) x + 2 = 5 & 2 + 2 = 4 & N o (b) x - 2 = 0 & 2 - 2 = 0 & Y e s (c) 2 x + 1 = 0 & (2 \times 2) + 1 = 5 & N o (d) x + 3 = 6 & (2 + 3) = 5 & N o \end{matrix}$

$∴$ The equation x - 2 = 0 has x = 2 as solution.