Question

Which of the following equations have $x=4\text{and}y=2$ as a solution?

• A. $2x+3y=12$
• B. $4x+y=19$
• C. $x+y=6$
• D. $3x+2y=15$

Answer 1

The correct option is C

$x+y=6$

Putting $x=4$ and $y=2$ in each of the given equations, we get the following:

$2x+3y=12$:
LHS $=2\times 4+3\times 2=14\ne$ RHS

$4x+y=19$:
LHS $=4\times 4+2=18\ne$ RHS

$x+y=6$:
LHS $=4+2=6=$ RHS

$3x+2y=15$:
LHS $=3\times 4+2\times 2=16\ne$ RHS

Hence, $x=4,y=2$ is a solution of the equation $x+y=6$.