Which of the following equations indicates the oxidising property of $H_{2} S O_{4}$ ?

H_{2} S O_{4} \to S O_{3} + H_{2} O

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H_{2} S O_{4} \to H_{2} S O_{3} + H_{2} O

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H_{2} S O_{4} \to S O_{2} + H_{2} O + [O]

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H_{2} S O_{4} \to S O_{3} + 2 [H]

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Solution

The correct option is C $H_{2} S O_{4} \to S O_{2} + H_{2} O + [O]$
In reaction C:
$H_{2} {S O}_{4} ⟶ {S O}_{2} + H_{2} O + [O]$

oxidation number of $S$ changes from $+ 6$ in $H_{2} {S O}_{4}$ to $+ 4$ in ${S O}_{2}$ and oxidation number of $O$ changes from $- 2$ in $H_{2} {S O}_{4}$ to $0$ in $[O]$ .

This shows oxidizing property of $H_{2} {S O}_{4}$ .

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Similar questions

S + O_{2} \to S O_{2}, △ H = - 298.2 k J m o l e^{- 1}

S O_{2} + 1 / 2 O_{2} \to S O_{3}, △ H = - 98.7 k J m o l e^{- 1}

S O_{3} + H_{2} O \to H_{2} S O_{4}, △ H = - 130.2 k J m o l e^{- 1}

H_{2} + 1 / 2 O_{2} \to H_{2} O, △ H = - 287.3 k J m o l e^{- 1}

H_{2} S O_{4}

298 K

C_{6} H_{12} O_{6} H_{2} S O_{4} (c o n c) - ----------- \to 6 C + 6 H_{2} O

H_{2} S O (d i l) + Z n C O_{3} ⟶ {Z n}^{2 +} + C O_{2} + S O_{4}^{2 -} + H_{2} O

H_{2} S O_{4} (d i l) + Z n ⟶ {Z n}^{2 +} + H_{2} + S O_{4}^{2 -}

5 H_{2} S O^{4} (c o n c) + 4 Z n ⟶ H_{2} S + 4 {Z n}^{2 +} + 4 S O_{4}^{2 -} + 4 H_{2} O

H_{2} S + {F e}^{3 +} ⟶ {F e}^{2 +} + S ↓ + H^{\oplus}

I^{⊖} + I O_{3}^{⊖} + H^{\oplus} ⟶ I_{2} + H_{2} O

B i (s) + N O_{3}^{⊖} + H^{\oplus} ⟶ N O_{2} + {B i}^{3 +} + H_{2} O

I^{⊖} + O_{2} (g) + H_{2} O ⟶ I_{2} + ⊖ O H

C u (s) + {A u}^{\oplus} ⟶ A u (s) + {C u}^{2 +}

Equation $H_{2} S + H_{2} O_{2} \to S + 2 H_{2} O$ represents

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