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Oxidation Number Method

Which of the ...

Question

Which of the following equations is balanced ?

5 B i O_{3}^{-} + 2 H^{+} + M n^{2 +} \to 5 B i^{3 +} + 7 H_{2} O + M n O_{4}^{-}

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5 B i O_{3}^{-} + 14 H^{+} + 2 M n^{2 +} \to 5 B i^{3 +} + 7 H_{2} O + 2 M n O_{4}^{-}

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2 B i O_{3}^{-} + 4 H^{+} + M n^{2} + \to 2 B i^{3 +} + 2 H_{2} O + M n O_{4}^{-}

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6 B i O_{3}^{-} + 12 H^{+} + 3 M n^{2 +} \to 6 B i^{3 +} + 6 H_{2} O + 3 M n O_{4}^{-}

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Solution

The correct option is B $5 B i O_{3}^{-} + 14 H^{+} + 2 M n^{2 +} \to 5 B i^{3 +} + 7 H_{2} O + 2 M n O_{4}^{-}$
Here, the number of atoms of each type and charges on both sides (left and right of the equation) are same. So, the equation is balanced.

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Similar questions

B i O_{3}^{-} + M n^{2 +} \to B i^{3 +} + M n O_{4}^{-} + H_{2} O

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O; E^{o} = X_{1} V

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O; E^{o} = X_{2} V

E^{o}

M n O_{4}^{-} + 4 H^{+} + 3 e^{-} \to M n O_{2} + 2 H_{2} O

E_{M n O_{4}^{-} | M n O_{2}}^{\circ}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O

E^{\circ} = 1.51 V

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O

E^{\circ} = 1.23 V

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O; E^{O} = 1.51 V; Δ G_{1}^{0} = - 5 \times 1.51 \times F

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O; E^{O} = 1.23 V; Δ G_{2}^{0} = - 5 \times 1.23 \times F

E_{M n O_{4}^{-} | M n O_{2}}^{\circ}

^{o}

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