Which of the following equations represents a transverse wave travelling along -y axis?

x = A sin (ω t - k y)

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x = A s i n (ω t + k y)

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y_{0} = A sin (ω t - k X)

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y_{0} = A s i n (ω t + k X)

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Solution

The correct option is B $x = A s i n (ω t + k y)$
$\begin{matrix} F o r n e g a t i v e y - a x i s s i g n o f ω t & k y s h o u l d b e s a m e x = A sin (ω t + k y) H e n c e, o p t i o n B i s c o r r e c t n a s w e r . \end{matrix}$

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Similar questions

y = A sin (ω t - k x)

y = A sin (ω t + k x)

Which of the following two wave equations can form stationary wave?

(i) $Y = A s i n (ω t - k x)$

(ii) $Y = A c o s (ω t - k x)$

(iii) $Y = A s i n (ω t + k x)$

(iv) $Y = A c o s (ω t + k x)$

y = a cos (ω t - k x)

x = 0

y_{1} = A sin (ω t - k x)

y_{2} = A sin (ω t - k x + \frac{π}{4})

y_{1} = A s i n (ω t - k x) a n d y_{2} = A s i n (ω t + k x)

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